alternate of that :

js2006 · 10-16-2006, 12:01 AM

hello guys i made a simple switch calculator , i want to add / improve it's output by taking a respone from user's after the program sucessfully shows calculation , the program asks users to :

Do another (y/n)? if y program re runs
if n the program exits.

please help me around , here it's code.

Code:

#include<iostream>
#include<stdlib.h>

using namespace std;
main()
{
    float a,b,ans;
    char op;
              cout << "Please enter number , Operator , 2nd Number to calculate\n";
              cin >> a >> op >> b;
    switch (op)
    {
        case '+':
        ans = a + b ;
        cout << "Sum of your inputted integers are \n";
        cout << ans;
        break;
        case '-':
        ans = a - b ;
        cout << "Substraction of your inputted integers are \n";
        cout << ans;
          break;
        case '*':
        ans = a * b ;
        cout << "Multiplication of your inputted integers are \n";
        cout << ans;
          break;
        case '/':
        ans = a / b ;
        cout << "Division of your inputted integers are \n";
        cout << ans;
   default:
       {
     
         cout << "you enter somethink un-expected";
 }    
 
         }
}

toe_cutter · 10-16-2006, 06:28 AM

Wrap it in a while loop and test for y or n with another cin.

Toe

teknomage1 · 10-16-2006, 05:21 PM

You could abstract that into a function:

Code:

bool y_or_n_p( void )
{
    //predicate function to prompt the user for a y or n character
    // and translate that into a boolean value

    char c;          //user input
    cout << "(y or n) ";
    //loop until one of the return conditions is met
    while ( 1 )
    {
        cin >> c;
        cin.ignore();

        if ( c == 'y' || c == 'Y' )
        {
             return true;
        }
        else if ( c == 'n' || c == 'N' )
        {
             return false;
        }
        else
        {
             //Prompt user more specifically
             cout << "Please enter y or n" << endl;
        }
    }
}

bool continue = y_or_n_p();

js2006 · 10-17-2006, 05:40 PM

there is a some problem , here plz help me up

Code:

bool continue =  y_or_n_p();

compiler is giving error on the c++ statment :

33 C:\Dev-Cpp\bin\check.cpp syntax error before `continue'

here is my code , plz improve it , may be my logic is wrong.

Code:

The output should around be that :

Enter first number, operator, second number: 10/3
Answer: 3.33333
Do another (y/n)?y
Enter first number, operator, second number: 12+100
Answer: 112
Do another (y/n)?n

my code to be improve :

Code:

#include<iostream>
#include<stdlib.h>

using namespace std;
bool y_or_n_p( void )
{
    //predicate function to prompt the user for a y or n character
    // and translate that into a boolean value

    char c;          //user input
    cout << "(y or n) ";
    //loop until one of the return conditions is met
    while ( 1 )
    {
        cin >> c;
        cin.ignore();

        if ( c == 'y' || c == 'Y' )
        {
             return true;
        }
        else if ( c == 'n' || c == 'N' )
        {
             return false;
        }
        else
        {
             //Prompt user more specifically
             cout << "Please enter y or n" << endl;
        }
    }
}
bool continue =  y_or_n_p();

main()
{
    float a,b,ans;
    
    char op;
              cout << "Please enter number , Operator , 2nd Number to calculate\n";
              cin >> a >> op >> b;
    switch (op)
    {
        case '+':
        ans = a + b ;
        cout << "Sum of your inputted integers are \n";
        cout << ans;
        
        break;
        
        case '-':
        ans = a - b ;
        cout << "Substraction of your inputted integers are \n";
        cout << ans;
          break;
        
        case '*':
        ans = a * b ;
        cout << "Multiplication of your inputted integers are \n";
        cout << ans;
          break;
        
        case '/':
        ans = a / b ;
        cout << "Division of your inputted integers are \n";
        cout << ans;
         
           break;
   default:
       {
     
         cout << "you enter somethink un-expected";
 }    
 
         }
         
}

teknomage1 · 10-17-2006, 07:58 PM

I don't think you're allowed to run fuctons outside of your main declaration.

js2006 · 10-17-2006, 08:05 PM

so many errors here : after i put the function inside main ,

where to place it perfectly and where and how to call it ??

teknomage1 · 10-17-2006, 10:46 PM

You don't put the function definition in main, you put the function call in main.

js2006 · 10-17-2006, 11:44 PM

i have put it , but it working not fine

the no n , N part works ok but

the Y,y part doesnot return true

it doesnot re-run the program.

thanks for your help.

redhead · 10-18-2006, 05:45 AM

The compile error is because the word "continue" is a key word, in any loops if you for some reason want to let it skip some parts add the continue instruction.
Thus you cant declare it as a variable.

js2006 · 10-18-2006, 07:27 AM

Here is the code , but the function doesnot return y ,Y and rerun Program after it successfully display calculation results.
so plz improve it.
iam learning it , tried so many times
but still stucked.

Thanks , Here is the code

Code:

#include<iostream>
#include<stdlib.h>

using namespace std;
bool y_or_n_p( void );

main()
{
    float a,b,ans;
    
    char op;
              cout << "Please enter number , Operator , 2nd Number to calculate\n";
              cin >> a >> op >> b;
    switch (op)
    {
        case '+':
        ans = a + b ;
        cout << "Sum of your inputted integers are \n";
        cout << ans;
        y_or_n_p();
        
        break;
        
        case '-':
        ans = a - b ;
        cout << "Substraction of your inputted integers are \n";
        cout << ans;
        y_or_n_p();
          break;
        
        case '*':
        ans = a * b ;
        cout << "Multiplication of your inputted integers are \n";
        cout << ans;
        y_or_n_p();
          break;
        
        case '/':
        ans = a / b ;
        cout << "Division of your inputted integers are \n";
        cout << ans;
         y_or_n_p();
           break;
   default:
       {
     
         cout << "you enter somethink un-expected";
 }    
 
         }
         

}        
bool y_or_n_p( void )
{
    //predicate function to prompt the user for a y or n character
    // and translate that into a boolean value

    char c;          //user input
    cout << "(y or n) ";
    //loop until one of the return conditions is met
    while ( 1 )
    {
        cin >> c;
        cin.ignore();

        if ( c == 'y' || c == 'Y' )
        {
             return true;
        }
        else if ( c == 'n' || c == 'N' )
        {
             return false;
        }
        else
        {
             //Prompt user more specifically
             cout << "Please enter y or n" << endl;
        }
    }
}

redhead · 10-18-2006, 09:05 AM

like Toe said

Quote:

Wrap it in a while loop and test for y or n with another cin.

so do it like this:

Code:

main()
{
    float a,b,ans;
    
    char op;
do{
    cout << "Please enter number , Operator , 2nd Number to calculate\n";
    cin >> a >> op >> b;
    switch (op)
    {
        case '+':
        ans = a + b ;
        cout << "Sum of your inputted integers are \n";
        cout << ans;
        break;
        
        case '-':
        ans = a - b ;
        cout << "Substraction of your inputted integers are \n";
        cout << ans;
          break;
        
        case '*':
        ans = a * b ;
        cout << "Multiplication of your inputted integers are \n";
        cout << ans;
          break;
        
        case '/':
        ans = a / b ;
        cout << "Division of your inputted integers are \n";
        cout << ans;
           break;
   default:
         cout << "you enter somethink un-expected";
  }
 }while(y_or_n_p())

}