Total beginner, need help with my code! Urgent timeframe

[cleverest]

Please someone help me, I'm supposed to come up with a C++ code to give the following dialog (user input capable text is in BOLD) I'm supposed to have one loop for full credit... but I'm not even concerned with that if I'm able to make this work some other way....what I have done so far is below and it's driving me nuts (I told you...I'm a total newbie!) :-D

I only have till midnight today!! Please someone help me out, I'll study it an learn it better then fighting with it all day and failing the challenge

(with the understanding that during
boom times, population increases by 15%. During bad times,
population decreases by 20%)

This is the desired dialog when the program is Run:

Enter a starting population size: 1000
After a boom year, your population has grown to:1150
After a bad year, your population has shrunk to:800
Continue(y/n)? y
Was it a boom or bad year (o/a)? o

Your starting population is now 1150
After a boom year, your population has grown to:1323
After a bad year, your population has shrunk to:920
Continue(y/n)? y
Was it a boom or bad year (o/a)? a

Your population is now 920
After a boom year, your population has grown to:1058
After a bad year, your population has shrunk to:736
Continue(y/n)? n
Was it a boom or bad year (o/a)? o

Your final population is 1058

#include <iostream>
using namespace std;


int main()
{
	double population = 0;
	double boom_year;
	double bad_year;
	char contin;
	char boomornot;

	cout << "Enter a starting population size: ";
	cin >> population;
	boom_year = (population * 1.15);
	bad_year = (population * 0.8);
	cout << "After a boom year, your population has grown to: " << boom_year << "\n";
	cout << "After a bad year, your population has shrunk to: " << bad_year << "\n";
	cout << "Continue(y/n)? "; // determines which IF statement below to acccess
	cin >> contin;

	if (contin == 'n') // I'm pretty confident with this section, it displays final result and then exits
	{
		cout << "Was it a boom or BAD year (o/a)? ";
		cin >> boomornot;
		if (boomornot == 'o')
	    {
		population = boom_year;
		cout << "Your final population is " << boom_year << "\n";
	    }
			if (boomornot == 'a')
	        {
		population = bad_year;
		cout << "Your final population is " << bad_year << "\n"; 
	        }
	
	}


	if (contin == 'y') // this section is a mess...it works, but can't loop and can't figure it out otherwise...HELP!
	{
		cout << "Was it a BOOM or bad year (o/a)? ";
		cin >> boomornot;
		if (boomornot == 'o')
	    {
		population = boom_year;
		cout << "Your starting population is now " << boom_year << "\n";
	    }
			if (boomornot == 'a')
	        {
		population = bad_year;
		cout << "Your starting population is now " << bad_year << "\n"; 
	        }
	
	}


	// need more code probably....can someone brilliant help me out??
	


	return 0;
}

[Valmont]

Something like this?

#include <iostream>
#include <cstring>
#include <cmath> //floor()

using namespace std;

const double BOOM_FACTOR = 1.15;
const double BAD_FACTOR = 0.8;

int main()
{
  double population = 0;
  char userChoice = 'y';
  
  cout << "Enter a starting population size: ";
  cin >> population;
  
  double PredictBoomPopulation;
  double PredictBadPopulation;
  
  //std::floor: 0.67 humans don't exist.
//Let's add 0.5 because of rounding errors during conversion.

  PredictBoomPopulation = floor(population* BOOM_FACTOR);
  PredictBadPopulation = floor(population *BAD_FACTOR);
  cout << "After a boom year, your population will grow to: "
    << PredictBoomPopulation << endl;
  cout << "After a bad year, your population will shrink to: "
    << PredictBadPopulation << endl;
  
  do
  {
    cout<<endl;        
    cout << "Was it a boom or BAD year (o/a)? ";
    cin >> userChoice;
    if (userChoice == 'o')
    {
      population = floor(PredictBoomPopulation);
    }
    if (userChoice == 'a')
    {
      population = floor(PredictBadPopulation);
    }

    cout<<"Population: "<<population<<endl<<endl;
    
    PredictBoomPopulation = floor(population* BOOM_FACTOR+.5);
    PredictBadPopulation = floor(population *BAD_FACTOR+.5);
    cout << "After a boom year, your population will grow to: "
        << PredictBoomPopulation << endl;
    cout << "After a bad year, your population will shrink to: "
        << PredictBadPopulation << endl;

    cout<<"Do you wish to continue program? (yes = y): ";
    cin>>userChoice;
  } while(userChoice == 'y');
  
  cout<<"Program terminated."<<endl;
   return 0;
}

[cleverest]

Wow very nice, I really appreciate you taking the time to answer my inquiry as quickly as you did, if you want to reply again to the following that would rock!

Otherwise, thanks a million anyways!!

Your code will help me understand how to loop the CONTINUE prompt and such ,for sure, but.....it does not match the top dialog exactly (He is probably super picky about that) so I'll have to play around with it to figure out these remaining issues.

for instance:

1. The 'CONTINUE (y/N)' prompt needs to be before the: 'Was it a boom or bad year (o/a)?' question. (even though regardless BOTH questions get outputted to the screen, this confuses little 'ol me)
2. When finally answering N to the continue prompt it should display the: 'Your final population is " ' and then terminate, instead of just terminating the program without the final population shown. (determined by the last 'was it a boom or bad year' prompt.....)
3. The cout text line "Population: ####" should NOT display after answering the Y/N or O/A prompts.

Also we have covered briefly SWITCHES, do you think that would make this code easier as a beginner for me to create??

Thanks again.

[Valmont]

For questions 1,2 and 3, you only need to move things up or down most likely. Just fiddle with it a bit.

On the switch issue, that is entirely up to you. Get the code right first, then see if you like a switch statement in this case.