help with already written program

[Androto]

#include <iostream>
#include <cstdlib>

using namespace std;
int squars (int x, float y=0);
int main()
{
	int i(1);
	squars (i);
  
	cout<< "\n"<< "The average is "<< i/100<< "\n";
	system("PAUSE");	
	return 0;
}  
int squars (int x, float y[0])
{
	while (x<=10)
	{
	     y = x * x + y;
		 cout<< x*x<< endl;
		 x++;
	}
	return y;
}

the average of the square roots won't work. what am i doing wrong?

[Valmont]

It is not clear to me what your mean with:
The average is " i/100
That is not an average of anything. Be more specific.
Furthermore, the code below contains a few changes. Also note that I changed floats into doubles. Use doubles as your default precision (in standard c++) unless there is a special reason not to.

#include <iostream>
#include <cstdlib>

using namespace std;

double squars (int x, double y=0);

int main()
{
  int i(1);
  squars (i);

  cout<< '\n'<< "The average is "<< i/100.0<< '\n';
  
  system("PAUSE");
  return 0;
}

double squars (int x, double y)
{
  while (x<=10)
  {
       y = x * x + y;
     cout<< x*x<< endl;
     x++;
  }
  return y;
}

[Androto]

why did you change th ints for the squars function into doubles as well?

i am trying to add up all the square roots, and display the average of all the square roots. the average should end up to be 38.5

[Androto]

on that tutorial site you posted, the definition of a double is: double precision floating point number. but what does that mean?



also, how would you include that other way of making the program pause at the end? i remember the words void being part of it.

[Androto]

i changed the code a bit, and now it works, but i still don't know how to do that system("pause") thing the way you did it.

 #include <iostream>
#include <cstdlib>

using namespace std;
double squars (int x, double y=0);



int main()
{
  int i(1);
  squars (i);
  
  system("PAUSE");
  return 0;
}



double squars (int x, double y)
{
  while (x<=10)
  {
       y = x * x + y;
     cout<< x*x<< endl;
     x++;
  }
  cout << "The average of the square roots is " << y/10 << endl;
  return y;
}

[Valmont]

Originally posted by Androto
why did you change th ints for the squars function into doubles as well?

Lets start with communication.
The first thing I wondered was: "what is squars?".
Then I hope to find out by analysing the squars() function. But it doesn't help me much. Then I look at the return type and the types it accepts as its arguments. What I see is this declaration:

double squars (int x, double y=0);

Then I see this implementation:

int squars (... float y[0])
{
	...	{
	     ...
		 ...
		 ...	}
	return y;
}

You are returning a "float", yet your function hints on returning an "int". I have nothing else but to gamble -return a float, and leave the rest. Or... return the int but change the second argument into an int.
I've chosen the first option. All of because I Don't know what a squars is.

Name your variables and functions right. Make sure a stranger (like me) knows what you mean and want.

********************************

Originally posted by Androto
on that tutorial site you posted, the definition of a double is: double precision floating point number. but what does that mean?



also, how would you include that other way of making the program pause at the end? i remember the words void being part of it.

To answer your first question:
It means it is twice as precise as a float(ing) point variable.

The answer to your second question is even more simple:
All you need to do is to go back to here http://codenewbie.com/forum/t2403.html and read my code. Copy and paste the functions then use them. That's all. It's for free too .

but i still don't know how to do that system("pause") the way you did it.

Well, if you are a bit more patient, then you will receive an answer too. Posting the same question twice within a few moments doesn't help . Read my answer above this one (the link) and you'll have your answer.