Easy (for you ninjas) loop question

[draven77]

Hey guys,
really dumb question that I know has a simple answer...

I have this loop that generates a dropdown list for years. The problem is that the first current year it grabs initially is great (06) after it is incremented, I loose my "0" before the 6.. i.e...

Returns: 06,7,8,9
Instead of: 06,07,08,09

I'm sure there's a function or something that preserves the double, but can't seem to find it.

Here's the loop

<select name="expire_year">
<?
$curYear = date("y");
$yearCount = 1;

   echo "<option value='' SELECTED>- Select -</option>\n";

while ($yearCount < 10) {
   echo "<option value='".$curYear."'>".$curYear."</option>\n";

   $yearCount ++;
   $curYear ++;
}
?>
</select>

[sde]

personally I would use date("Y") so you have the 4 digit year. since they don't start with "0" you won't have this problem.

you could also create a string array with predefined dates:

PHP Code:

<?
$years = array("06","07","08","09","10");
foreach ($years as $year) {
  echo "<option value='".$year."'>".$year."</option>\n";
}
?>

or str_pad if you want to keep using your way

PHP Code:

<?
$year = date("y");

while($year < 10) {
  $year = str_pad($year, 2, "0", STR_PAD_LEFT);

  echo "<option value='".$year."'>".$year."</option>\n";

  $year++;
}
?>

hth

[draven77]

The reason i have to keep it like that is because it's getting passed to Authorize.net..

they require the expiration date to be sent in "mmyy".

So, i have 2 drop downs, one for month and one for year.
Then when I process it, i combine them.
$expire_date = $month.$year;

But it doesn't accept the expire date if for example it got May 08 as "508". It would have to be 0508.

I'm writing this loop so it isn't hard-coded and I don't have to update it next year. make sense ??

Thanks for the input!!

[sde]

yes makes sense. you might want to set your end year dynamically too then..

$end_year = $cur_year + 6;

then you won't have to update your end year next year as well.

[nudave04]

What about just appending the 0 as text when necessary? (Also, no need to increment a counter, just set an end point)

$curYear = floor(date("y"));
$endYear = $curYear + 10;

   echo "<option value='' SELECTED>- Select -</option>\n";

while ($curYear < $endYear) {
   if ($curYear < 10) {
        $displayYear = "0".$curYear;
        } else {
        $displayYear = $curYear;
    }
   echo "<option value='".$displayYear."'>".$displayYear."</option>\n";
   $curYear ++;
}

[draven77]

Very nice, nudave04.. I like that option a lot.

simple, not overthought. great.
And I can understand it

Thanks guys! you all rulzor !

[teknomage1]

That's cool that it all makes sense. Another cool thing is that

PHP Code:

$displayYear = str_pad($year, 2, "0", STR_PAD_LEFT); 


is equivalent to

PHP Code:

   if ($curYear < 10) {
        $displayYear = "0".$curYear;
        } else {
        $displayYear = $curYear;
    } 


So now you can plug that into nudave04's loop and get

PHP Code:

while ($curYear < $endYear) {
   $displayYear = str_pad($curYear, 2, "0", STR_PAD_LEFT);
   echo "<option value='".$displayYear."'>".$displayYear."</option>\n";
   $curYear ++;
} 


[DJMaze]

or

PHP Code:

echo "<option value='' selected='selected'>- Select -</option>\n";

$curYear = (int) date('y');
for ($i=0; $i < 10; ++$i) {
   $displayYear = str_pad($curYear+$i, 2, '0', STR_PAD_LEFT);
   echo "<option value='$displayYear'>$displayYear</option>\n";
} 


[sde]

i think i'll write a book .. 101 ways to code a year drop down in PHP

[redhead]

Or more simplyfied:

PHP Code:

echo "<option value='' SELECTED>- Select -</option>\n";
for ($i=floor(date("y")), $j=$i+10; $i < $j; ++$i)
   printf("<option value='%.2d'>%.2d</option>\n", $i, $i); 


But then again there are hundreds of ways you can form something like this.