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05-14-2004, 01:36 PM
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#1 (permalink)
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Registered User
Join Date: May 2004
Location: Kellogg, Idaho
Posts: 2
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Trouble inserting multiple records into table, Please someone help me! Thanks
Hi all how are you? I am just having a bit of an issue with my form script and mysql, inserting records from this form of mine into my table in my database.
it looks like all my others and they work, so what could be so wrong with this. Here
let me show you the code
CODE
PHP Code:
<?php
$host="xxxxxxxxx";
$username="xxxxxxx";
$password="xxxxxx";
$db="xxxxx";
$link=mysql_connect($host,$username,$password);
if (!$link)
die("Couldn't connect to MySQL");
mysql_select_db($db,$link)
or die("couldn't open $db:".mysql_error());
$sender_firstandlast =$_POST['sender_firstandlast'];
$sender_companyname =$_POST['sender_companyname'];
$sender_email=$_POST['sender_email'];
$sender_phonenumber=$_POST['sender_phonenumber'];
$how_recieve=$_POST['how_recieve'];
$websitetitle=$_POST['websitetitle'];
$what=$_POST['what'];
$websitedetails=$_POST['websitedetails'];
$websitebudget=$_POST['websitebudget'];
$how_pages=$_POST['how_pages'];
$completiondate=$_POST['completiondate'];
$currenturl=$_POST['currenturl'];
$chooseany=$_POST['chooseany'];
$size=$_POST['size'];
$scripts=$_POST['scripts'];
$databases=$_POST['databases'];
$scriptdetails=$_POST['scriptdetails'];
mysql_select_db($db) or die("Cannot select the database.<br>" . mysql_error());
$result=mysql_query("INSERT INTO quote (sender_firstandlast, sender_companyname, sender_email, sender_phonenumber, how_recieve, websitetitle, what, websitedetails, websitebudget, how_pages, completiondate, currenturl, chooseany, size, scripts, databases, scriptdetails) VALUES ('$sender_firstandlast','$sender_companyname','$se nder_email','$sender_phonenumber','$how_recieve',' $websitetitle','$what','$websitedetails','$website budget','$how_pages','$completiondate','$currentur l','$chooseany','$size','$scripts','$databases','$ scriptdetails')")or die("Insert Error: ".mysql_error());
?>
<?php
include("steveform.php");
?>
All my other scripts use this for their inserting data and so why doesn't this work. The variables are all set right im sure. They carry the same name= as in the form names. the names are correct in the Database Table. May be I entered the data the wrong way in my database??? I don't know, I've tried everything and my form is not running, well dumby me i need to put up my backup, duh, but in the mean time i would really like to solve this, please help me anyone. thanks
Last edited by sde; 05-14-2004 at 03:25 PM.
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05-14-2004, 02:48 PM
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#2 (permalink)
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LOAD "*",8,1
Join Date: Feb 2003
Location: la.ca.us
Posts: 254
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and your error message is...?
what does php print out? what is in the mysql log? also do yourself a favor and print out the sql statement that you're passing to mysql_query(), so that you (and us) can look at what is actually being given to the database.
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05-14-2004, 03:30 PM
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#3 (permalink)
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Moderator
Join Date: May 2002
Location: us.ca
Posts: 4,489
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yes, as joe said, please post the errors .. if you are not getting errors for some reason, try troubleshooting the sql query itself. below, i make a string called $sql and echo it to the screen.
an easy way to test to see if this is a good sql query or not is paste the output into phpmyadmin and see if it reports any errors.
PHP Code:
$sql = "INSERT INTO quote (sender_firstandlast, sender_companyname, sender_email, sender_phonenumber, how_recieve, websitetitle, what, websitedetails, websitebudget, how_pages, completiondate, currenturl, chooseany, size, scripts, databases, scriptdetails) VALUES ('$sender_firstandlast','$sender_companyname','$se
nder_email','$sender_phonenumber','$how_recieve','
$websitetitle','$what','$websitedetails','$website
budget','$how_pages','$completiondate','$currentur
l','$chooseany','$size','$scripts','$databases','$
scriptdetails')";
echo $sql;
__________________
Mike
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05-14-2004, 05:59 PM
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#4 (permalink)
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Senior Contributor
Join Date: May 2002
Location: vta.ca.usa
Posts: 555
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This has already been answered on another forum site. 'databases' is a MySQL reserved word. Is there something you don't understand about that?
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