PHP Command-Line Arguments?

[Antagony]

I use PHP in a linux environment, and as such, I have use of the command-line interface, e.g. "# php crap.php"

I was wondering if it was possible to pass command-line arguments to a php script, e.g. "# php crap.php http://www.codenewbie.com"

Is that possible? If so, what environment variables do I need to look at?

Thanks.

[Antagony]

Okay, I answered my own question.

If you've used C/C++, then you'll pick this up easily. There are two variables, "$argc" and "$argv".

$argc is "argument counter". It's an integer that represents the number of arguments passed to the script PLUS ONE (the name of the script being executed).

Example, "# php crap.php crap rocks"
$argc would hold the value "3".

$argv is "argument value". It's an array that contains an argument (as a string) in each array key, with the name of the script being in $argv[0] and the arguments passed being held after that.

Example, "# php crap.php crap rocks"
$argv[0] = "crap.php"
$argv[1] = "crap"
$argv[2] = "rocks"

Make sense? I'm pretty sure that's how things go anyway, I haven't actually typed out any code for it yet, but I'm about to do so. So if I'm wrong, I'll come back and fix this post

[sde]

that is great question/answer! i was searching for an answer, and then i found it here =)

that is correct info too according to other sources. :rock:

[Antagony]

Glad you found it useful

[bisnaguete]

Very direct and precise.