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Thraxian · 12-18-2003, 09:46 AM

Another VB Example:

Code:

Public Function LetterCount(Text As String, Letter As String) As Long
   LetterCount = Len(Text) - Len(Replace$(Text, Letter, vbNullString))
End Function

As to the first post, it had errors in my VB environment. Split returns a string array, not a string. Also, Return is not valid in this context; instead, the result should be assigned to the function variable. Unless, this is VB.NET, in which case, the language was not clearly specified.

12-18-2003, 09:46 AM	#14 (permalink)
Thraxian Registered User Join Date: Aug 2003 Location: NC, USA Posts: 1	Another VB Example: Code: Public Function LetterCount(Text As String, Letter As String) As Long LetterCount = Len(Text) - Len(Replace$(Text, Letter, vbNullString)) End Function As to the first post, it had errors in my VB environment. Split returns a string array, not a string. Also, Return is not valid in this context; instead, the result should be assigned to the function variable. Unless, this is VB.NET, in which case, the language was not clearly specified.