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First of, try and see how many dolars it fits into, say he has 881 pennies, that would be 8 dolars, then theres 81 pennies left. take the highest number of quaters it would be, which is 3, that'll leave you with 11 pennies, then take the highest number of dimes that'll provide, which is zero, this will leave 11 pennies, then take the highest number of nickels that'll provide, which is two, which will leave you with 1 pennie...
So the outcome to that will be:
Dollars: 8
Quarters: 3
Dimes: 0
Nickels: 2
Pennies: 1
Anyway, you will allways use the greed paradigm..
Last edited by redhead; 02-04-2007 at 12:30 PM.
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