So in your code, "c" is nothng but an "object reference". So when you pass it to your ID function, you will pass a COPY OF THE REFERENCE.
Aha, now I see what Java is about
.
So you could "alter" the value(s) in "c" but you cannot interchange it with other objects if passed to the same function (like a "b" for example).
You need to use the original references for that.
That's what I understood from that text.
So try your experiment like this:
- Make a swap function.
- Give objects b and c a value in main. (your current customer objects will do just fine).
- pass them to your swap function.
- swap them.
- test in main: fails.
- in swap function: assign new value (name and id) to "c".
- test in main: success, value of c has changed.
Watch it, strings are passed by VALUE. No copies of references are made.
And it is certainly not a reference like in C++.
That's what I understood from that story. But you gotta test it in the swap function I proposed. I don't have Java.